LinkedIn Tango #758 Answer (November 4, 2026)

6×6 grid · 12 given cells · 6 = and × signs · Nov 4, 2026

Our solver gets there in 21 reasoning steps, 2 of them try-and-see.

Hints and the full solution for the LinkedIn Tango puzzle of November 4, 2026.

Tango #758, redrawn. Fill every cell with a sun or a moon: 3 of each in every row and column, never three alike in a row; = means the same, × means opposite.

Hints for Tango #758

CheckCheck the cells you have so far

Copy what you have filled in (tap once for a sun, twice for a moon) and press Check: we say how many cells are wrong and mark only the first.

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Hint 1Cells that follow from the givens

Four simple rules: two of a kind side by side push the opposite to both ends; a gap between two of a kind takes the opposite; = and × copy or flip a neighbour; and a line that already has its 3 of one symbol takes the other. They alone fill these 2 cells:

Hint 2Rows 3–4 filled in

Rows 3–4 complete. Each row and column needs 3 suns and 3 moons, so count what is left in every line.

Tango #758 answer

Show the full solution

Row by row, left to right:

Row 1: moon, moon, sun, sun, moon, sun
Row 2: moon, sun, sun, moon, sun, moon
Row 3: sun, moon, moon, sun, moon, sun
Row 4: moon, moon, sun, moon, sun, sun
Row 5: sun, sun, moon, moon, sun, moon
Row 6: sun, sun, moon, sun, moon, moon

✓ Checked Nov 4, 12:02 AM Pacific: our solver filled the grid on its own and confirmed this is the only answer. How we check

How to solve Tango #758, step by step

Our solver's reasoning, in an order you can follow without guessing. In each picture the ringed cells are the ones that move fills, and the outline shows the row, column or pair it looked at.

Show all 21 steps (this gives the answer away)

Two moons side by side in column 1: the cell next to them (row 3) must be a sun, or there would be three moons in a row.
Column 3 has a pair of suns, so row 3 beside them gets a moon: a third sun would make three in a row.
Suppose row 6, column 3 were a sun. Following the rules from there (3 forced cells), column 3 would get three moons in a row. So row 6, column 3 is a moon.
The × between row 6, column 3 and row 6, column 4 means they are opposite. Row 6, column 3 is a moon, so row 6, column 4 is a sun.
The = pair (row 6, column 1 and row 6, column 2) holds two of the same. Next to it, row 6, column 3 is a moon, so the pair can’t be moons (three in a row): both are suns.
Row 6 is full up on suns: columns 5 and 6 take moons.
Suppose row 5, column 5 were a moon. Following the rules from there (3 forced cells), column 5 would get more than 3 moons. So row 5, column 5 is a sun.
Row 5, column 5 is a sun, and the × next to it flips that: row 5, column 6 is a moon.
A third moon can’t join the pair in column 6, so row 4 is a sun.
Column 6 already has its 3 moons, so its last empty cell (row 3) is a sun.
The = pair (row 5, column 3 and row 5, column 4) holds two of the same. Next to it, row 5, column 5 is a sun, so the pair can’t be suns (three in a row): both are moons.
A third moon can’t join the pair in row 5, so column 2 is a sun.
The = between row 5, column 1 and row 5, column 2 means they are the same. Row 5, column 2 is a sun, so row 5, column 1 is a sun.
Column 1 has a pair of suns, so row 4 beside them gets a moon: a third sun would make three in a row.
A third sun can’t join the pair in column 2, so row 4 is a moon.
Two moons side by side in row 4: the cell next to them (column 3) must be a sun, or there would be three moons in a row.
With three suns already in column 2, row 3 has to be a moon.
A third moon can’t join the pair in row 3, so column 4 is a sun.
Column 5 of row 3 sits between two suns, so it has to be a moon.
With three suns already in column 4, row 4 has to be a moon.
Row 4 is full up on moons: column 5 takes a sun.